A perfect number \(P\) is equal to the sum of its divisors (where
the divisors include \(1\), but not \(P\) itself).
- Euclid: If \(2^n-1\) is prime
then \(2^{n-1}(2^n-1)\) is perfect
- Euler: all even perfect numbers are of the form \(2^{p-1}(2^p-1)\),
where \(2^p-1\) is a Mersenne
prime (and so \(p\) is prime).
- 6 = 1 + 2 + 3 = 2 (22-1)
- 28 = 1 + 2 + 4 + 7 + 14 = 22
(23-1)
- 496 = 1 + 2 + 4 + 8 + 16 + 31 +
62 + 124 + 248 = 24 (25-1)
- 8128 = 1 + 2 + 4 + ... + 64 + 127
+ ... + 4064 = 26 (27-1)
- 33,550,336 = 1 + ... + 4096 + 8191
+ ... + 16775168 = 212 (213-1)
- 8,589,869,056 = 1 + ... + 65536 + 131071
+ ... + 4294934528 = 216 (217-1)
- 137,438,691,328 = 1 + ... + 262144 +
524287 + ... + 68719345664 = 218 (219-1)
- ...
- Every even perfect number ends in a '6' or an '8'.
- All even perfect numbers are triangular numbers.
- 6 = 1 + 2 + 3 = 1 + 2 + (22-1)
- 28 = 1 + 2 + 3 + ... + 7 = 1 + 2 + 3 + ... + (23-1)
- 496 = 1 + 2 + 3 + ... + 31 = 1 + 2 + 3 + ... + (25-1)
- 8128 = 1 + 2 + 3 + ... + 127 = 1 + 2 + 3 + ... + (27-1)
- 33,550,336 = 1 + 2 + 3 + ... + 8191 = 1 + 2 + 3 + ... +
(213-1)
- 8,589,869,056 = 1 + 2 + 3 + ... + 131071 = 1 + 2 + 3 +
... + (217-1)
- 137,438,691,328 = 1 + 2 + 3 + ... + 524287 = 1 + 2 + 3
+ ... + (219-1)
- ...
- general result:
\( n: \mathbb{N} \vdash 2^{n-1} (2^n-1) = 1 + 2 + 3+ \ldots + (2^n-1)\)
- Every even perfect number, other than 6, is the sum of consecutive
odd cubes.
- (6, with p=2, does not fit the pattern)
- 28 = 13 + 33 = 13 + (2(3+1)/2-1)3
- 496 = 13 + 33 + 53 + 73
= 13 + 33 + 53 + (2(5+1)/2-1)3
- 8128 = 13 + 33 + ... + 153 =
13 + 33 + ... + (2(7+1)/2-1)3
- 33,550,336 = 13 + 33 + ... + 1273
= 13 + 33 + ... + (2(13+1)/2-1)3
- 8,589,869,056 = 13 + 33 + ... + 5113
= 13 + 33 + ... + (2(17+1)/2-1)3
- 137,438,691,328 = 13 + 33 + ... + 10233
= 13 + 33 + ... + (2(19+1)/2-1)3
- ...
- conjecture:
\( n: \mbox{Odd}\, ?{\vdash}\, 2^{n-1} (2^n-1) = 1^3 + 3^3 + \ldots + (2^{(n+1)/2}-1)^3 \)
- No odd perfect numbers are known, but if one does exist, a
lot is known about it:
- it is a perfect square multiplied by an odd power of a single
prime
- it has at least 8 distinct prime factors
- it has at least 75 prime factors (not necessarily distinct)
- its largest prime factor greater that 107
- its second largest prime factor is greater that 104
- its third largest prime factor is greater that 102
- it is divisible by a prime
component greater that 1020
Exhaustive computer search has shown that there are no odd perfect
numbers less than 10300.
[My thanks to Douglas Iannucci and Joshua
Zelinsky for some of this information, some of which is from the work of
Kevin Hare.]