Question 1: Using SPSS, cross-tabulate housing tenure by prematurity and carry out a chi-squared test.
We choose Analyze, Descriptive Statistics, Crosstabs. Put the variable 'Housing tenure' into Row(s): and 'Prematurity' into Column(s):. Click Statistics, Chisquare, Continue. Click OK.
You should get the case processing summary and then the following:
|Housing tenure * Prematurity Crosstabulation|
|Value||df|| Asymp. Sig. |
|N of Valid Cases||1443|
| a 2 cells (20.0%) have expected count less than 5.
The minimum expected count is 2.68.
As often happens, SPSS prints out more than you need. We should ignore the likelihood ratio (beyond the scope of our course) and the linear-by-linear association (not appropriate for this table).
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Last updated: 10 November, 2006.
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